Online JudgeProblem SetAuthorsOnline ContestsUser
Web Board
Home Page
F.A.Qs
Statistical Charts
Problems
Submit Problem
Online Status
Prob.ID:
Register
Update your info
Authors ranklist
Current Contest
Past Contests
Scheduled Contests
Award Contest
User ID:
Password:
  Register
Language:
Power Hungry Cows
Time Limit: 1000MSMemory Limit: 30000K
Total Submissions: 4708Accepted: 1160

Description

FJ's cows would like to be able to compute integer powers P (1 <= P <= 20,000) of numbers very quickly, but need your help. Because they're going to be computing powers of very large numbers, they can only keep around two work variables for intermediate results.

The first of those work variables is initialized to the number (denoted x) for which they are calculating the power; the other is initialized to 1. The cows can both multiply and divide any pair of the work variables and store the result in any work variable, but all results are stored as integers.

For example, if they want to compute x^31, one way to perform the calculation is:
                                              WV1  WV2

Start: x 1
Multiply first by first, store in second: x x^2
Multiply second by second: x x^4
Multiply second by second: x x^8
Multiply second by second: x x^16
Multiply second by second: x x^32
Divide second by first: x x^31

Thus, x^31 can computed in six operations. Given the power to be computed and the the number of work variables, find the minimum number of operations to calculate the power.

Input

A single line with one integer: P.

Output

A single line with a single integer that is the minimum number of operations it requires to compute the power.

Sample Input

31

Sample Output

6

Source

[Submit]   [Go Back]   [Status]   [Discuss]

Home Page   Go Back  To top


All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator